Wire / cable voltage drop calculator and how to calculate.
* @ 68°F or 20°C
** Results may change with real wires: different resistivity of material and number of strands in wire
The voltage drop V in volts (V) is equal to the wire current I in amps (A) times 2 times one way wire length L in feet (ft) times the wire resistance per 1000 feet R in ohms (Ω/kft) divided by 1000:
Vdrop (V) = Iwire (A) × Rwire(Ω)
= Iwire (A) × (2 × L(ft) × Rwire(Ω/kft) / 1000(ft/kft))
The voltage drop V in volts (V) is equal to the wire current I in amps (A) times 2 times one way wire length L in meters (m) times the wire resistance per 1000 meters R in ohms (Ω/km) divided by 1000:
Vdrop (V) = Iwire (A) × Rwire(Ω)
= Iwire (A) × (2 × L(m) × Rwire (Ω/km) / 1000(m/km))
The line to line voltage drop V in volts (V) is equal to square root of 3 times the wire current I in amps (A) times one way wire length L in feet (ft) times the wire resistance per 1000 feet R in ohms (Ω/kft) divided by 1000:
Vdrop (V) = √3 × Iwire (A) × Rwire (Ω)
= 1.732 × Iwire (A) × (L(ft) × Rwire (Ω/kft) / 1000(ft/kft))
The line to line voltage drop V in volts (V) is equal to square root of 3 times the wire current I in amps (A) times one way wire length L in meters (m) times the wire resistance per 1000 meters R in ohms (Ω/km) divided by 1000:
Vdrop (V) = √3 × Iwire (A) × Rwire (Ω)
= 1.732 × Iwire (A) × (L(m) × Rwire (Ω/km) / 1000(m/km))
The n gauge wire diameter dn in inches (in) is equal to 0.005in times 92 raised to the power of 36 minus gauge number n, divided by 39:
dn (in) = 0.005 in × 92(36-n)/39
The n gauge wire diameter dn in millimeters (mm) is equal to 0.127mm times 92 raised to the power of 36 minus gauge number n, divided by 39:
dn (mm) = 0.127 mm × 92(36-n)/39
The n gauge wire's cross sercional area An in kilo-circular mils (kcmil) is equal to 1000 times the square wire diameter d in inches (in):
An (kcmil) = 1000×dn2 = 0.025 in2 × 92(36-n)/19.5
The n gauge wire's cross sercional area An in square inches (in2) is equal to pi divided by 4 times the square wire diameter d in inches (in):
An (in2) = (π/4)×dn2 = 0.000019635 in2 × 92(36-n)/19.5
The n gauge wire's cross sercional area An in square millimeters (mm2) is equal to pi divided by 4 times the square wire diameter d in millimeters (mm):
An (mm2) = (π/4)×dn2 = 0.012668 mm2 × 92(36-n)/19.5
The n gauge wire resistance R in ohms per kilofeet (Ω/kft) is equal to 0.3048×1000000000 times the wire's resistivity ρ in ohm-meters (Ω·m) divided by 25.42 times the cross sectional area An in square inches (in2):
Rn (Ω/kft) = 0.3048 × 109 × ρ(Ω·m) / (25.42 × An (in2))
The n gauge wire resistance R in ohms per kilometer (Ω/km) is equal to 1000000000 times the wire's resistivity ρ in ohm-meters (Ω·m) divided by the cross sectional area An in square millimeters (mm2):
Rn (Ω/km) = 109 × ρ(Ω·m) / An (mm2)